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Rename variable value to val
The parameter value variable has the same name with the original value causes error 'index out of range' when calling value[index] in the next lines.
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4 additions
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4 deletions
| @@ -227,11 +227,11 @@ class HeaderValue { | @@ -227,11 +227,11 @@ class HeaderValue { | ||
| 227 | parameters[name] = null; | 227 | parameters[name] = null; |
| 228 | return; | 228 | return; |
| 229 | } | 229 | } |
| 230 | - var value = parseParameterValue(); | ||
| 231 | - if (name == 'charset' && value != null) { | ||
| 232 | - value = value.toLowerCase(); | 230 | + var val = parseParameterValue(); |
| 231 | + if (name == 'charset' && val != null) { | ||
| 232 | + val = val.toLowerCase(); | ||
| 233 | } | 233 | } |
| 234 | - parameters[name] = value; | 234 | + parameters[name] = val; |
| 235 | bump(); | 235 | bump(); |
| 236 | if (done()) return; | 236 | if (done()) return; |
| 237 | if (value[index] == valueSeparator) return; | 237 | if (value[index] == valueSeparator) return; |
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